The Picard theorem follows from Bloch's theorem in one variable.
It is then interesting to ask whether the same is possible in the case of
-holomorphic mappings in
. However, here we can directly find a Picard theorem without
invoking our Bloch theorem.
Theorem 10 (Picard)
Let
. If there are two bicomplex numbers
such that is invertible and for which the set
is not in the range of , then is constant.
Proof.
We have just to apply the so-called ``little Picard theorem" [15] to
and . The fact that is invertible will
insure us that will be equal to a bicomplex
number
with and nonzero.
Let
,
. Suppose
takes the value at .
There exist
such that
.
Thus,
Contradiction.
Hence, omits .
Similarly, omits , omits and omits .
Since
, and are
distinct. Similarly
.
In the same way, it is possible to find also a
Casorati-Weierstrass theorem:
Theorem 11 (Casorati-Weierstrass)
Let
with not identically noninvertible. Then,
is dense in
.
Proof.
The hypotheses imply that we can write
with
and nonconstant. Then we
can apply the Casorati-Weierstrass theorem for
to and in order to prove that
is dense in
.
A famous example of Fatou and Bieberbach (see [10])
shows that the usual formulation of the Picard theorem
in
does not extend to holomorphic mappings in .
In this connection, we have some interesting consequences of Theorem 11 which can be interpreted as an other kind
of little Picard theorem for bicomplex numbers:
Corollary 1
There is no nondegenerate -holomorphic mapping
such that
contains a ball.
Corollary 2
Fatou-Bieberbach examples cannot be -holomorphic
mappings, i.e. they connot satisfy
the complexified Cauchy-Riemann equations.
For a beautiful formulation of Picard's theorem which holds
in
higher dimensions, see [9]. Also, for a version of Picard's
theorem for quasiregular mappings see Rickman [12].
suivant:Bibliographie monter:A Bloch Constant for précédent:-holomorphy and quasiregularityDominic Rochon 2000-07-26